Mathematics
Stezzi347
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02.03) find the non-extraneous solutions of the square root of the quantity x plus 7 minus 4 equals quantity x plus 3 . (1 point) x = −2 x = −7 and x = −2 x = −6 and x = −7 x = 1

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[latex]\sqrt{x+7}-4=x+3\\ \sqrt{x+7}=x+3+4=x+7\\x+7=(x+7)^2=x^2+14x+49\\x^2+13x+42=0\\x^2+6x+7x+42=0\\x(x+6)+7(x+6)=0\\(x+7)(x+6)=0\\x=-7 \ and \ x=-6[/latex]

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