Mathematics
jamonrodrigues
13

5x + 7/x^2-2x-8 - 2x+19/x^2x-8

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(1) Answers
Koshi798

Since they have the same denominator, you just subtract the numerators: = (5x + 7 - 2x - 19)/(x^2 - 2x - 8) = (3x - 12)/(x^2 - 2x - 8) To solve the first factor, you factorize by taking what's common The common between 3x and 12 is 3 So it becomes 3(x - 4) dividing 3x and 12 each by 3 To factorize the quadratic equation x^2 - 2x - 8, you have to find two numbers if you add them they give you b which is -2, and if you multiply them they give you c which is -8 You get the two numbers -4 and 2 So the factorization of the quadratic equation is (x - 4)(x + 2) which is generally in the form of (x + s1)(x + s2) So you get: 3(x - 4)/(x - 4)(x + 2) You divide the numerator and the denominator by the factor (x - 4) So you get as a final answer: 3/(x + 2)

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