Mathematics
Telendez100
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8c^2-88c+242 How do you solve this?

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lyssie11234

[latex](a-b)^2=a^2-2ab+b^2[/latex] [latex]8c^2-88c+242=0\ \ \ /:2\\\\4c^2-44c+121=0\\\\(2c)^2-2\cdot2c\cdot11+11^2=0\\\\(2c-11)^2=0\iff2c-11=0\to2c=11\ \ /:2\to c=5.5[/latex] [latex]8c^2-88c+242=2(4c^2-44c+121)=2\left[(2c)^2-2\cdot2c\cdot11+11^2\right]\\\\=2(2c-11)^2[/latex]

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