Chemistry
lizzyfuentes
17

a .35 m solution of weak acid, HX, has a h+ of 4.15×10^-3. what is the value of ka for this acid

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(1) Answers
Czarny333

Ka has the formula: Ka = [H+] [X-] / [HX] We have the following given: [H+] = 4.15x10^-3 [HX] = 0.35 Since the acid dissociates in a ratio of 1 [H+] to 1 X, [H+] = [X-] Plugging in the values, Ka = (4.15x10^-3)(4.15x10-3) / 0.35 Ka = 4.92x10^-5

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