a .35 m solution of weak acid, HX, has a h+ of 4.15×10^-3. what is the value of ka for this acid

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(1) Answers

Czarny333

Ka has the formula:
Ka = [H+] [X-] / [HX]
We have the following given:
[H+] = 4.15x10^-3
[HX] = 0.35
Since the acid dissociates in a ratio of 1 [H+] to 1 X,
[H+] = [X-]
Plugging in the values,
Ka = (4.15x10^-3)(4.15x10-3) / 0.35
Ka = 4.92x10^-5