a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what is the net force on the runner? c.) how far does the sprinter travel during the 3 s?
Part A: Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is, a = (Vf - Vi) / t where a is acceleration, Vf is final velocity, Vi is initial velocity, and t is time Substituting, a = (9 m/s - 0 m/s) / 3 s = 3 m/s² ANSWER: 3 m/s² Part B: From Newton's second law of motion, the net force is equal to the product of the mass and acceleration, F = m x a where F is force, m is mass, and a is acceleration Substituting, F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N ANSWER: 240 N Part C: The distance that the sprinter travel is calculated through the equation, d = V₀t + 0.5at² Substituting, d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)² d = 13.5 m ANSWER: d = 13.5 m