a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what is the net force on the runner? c.) how far does the sprinter travel during the 3 s?

(1) Answers

Part A:  Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,              a = (Vf - Vi) / t where a is acceleration, Vf is final velocity, Vi is initial velocity, and t is time Substituting,             a = (9 m/s - 0 m/s) / 3 s = 3 m/s² ANSWER: 3 m/s² Part B:  From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,                F = m x a where F is force, m is mass, and  a is acceleration Substituting,               F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N ANSWER: 240 N  Part C:  The distance that the sprinter travel is calculated through the equation,          d = V₀t + 0.5at² Substituting,             d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²              d = 13.5 m ANSWER: d = 13.5 m

Add answer