Mathematics
KingBertman664
5

[FIND THE SUM]1+3+5+....+499]

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(2) Answers
Kubesh678

SUM = (1+2+3+....+500) - (2+4+.....+500) = (500*501)/2 - 2*(1+2+....+250) = 250*501 - 250*251 = [latex] 250^{2} .[/latex]

sarama2003

This question have a formül, This suM is  ;) [(first term+last term)/2)]*[[(last term-first term)/accrual]+1] [([latex]1+499[/latex]/[latex]2[/latex])]*[([latex]499-1[/latex])/[latex]2[/latex]+[latex]1[/latex]] [[ [latex]( \frac{500}{2} )[/latex]x[latex] \frac{498}{2} +1[/latex]  ]] [[ [latex]250*250[/latex] ]] [[ [latex]250^{2} [/latex] ]] [[ [latex]62500[/latex] ]] :)) 

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