Mathematics
ValorieMins86
22

How do I solve for x? log (x-2) = -1 + log (x+1)

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(1) Answers
Varykoksana

For this question you can say: log(x-2) - log(x+1) = -1  and you should know that log(x-2) minus log(x+1) is equal to: log((x-2)/(x+1))  so now you have: log((x-2)/(x+1)) = -1  now you can say: (x-2)/(x+1) = 10^ -1 or (x-2)/(x+1) = 1/10  now you can say: 10(x-2) = x+1  10x -20 = x +1  10x - x = 20+1  9x = 21  x = 21/9  x = 7/3 :))) I hope this is helpful have a nice day

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