How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 70% antifreeze? Use the six-step method.

Question

Mathematics

keishacontreras

Jul 17, 2020, 4:14:00 AM

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How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 70% antifreeze? Use the six-step method.

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(2) Answers

Answer 1 · 2020-07-17T15:56:42+03:00

0.7X+0.25*100=0.6(100+X) 0.7X+25=60+0.6X 0.7X-0.6X=60-25 0.1X=35 X=35/0.1 X=350 GALLONS OF 70%

Answer 2 · 2020-07-18T01:55:47+03:00

We have 100 gallons of 25% antifreeze. How much of 80% antifreeze do we need to add to make a 70% solution? .25 * 100 + .80x = .70 * 100 + x 25 + .80x = 70 + .7x .1x = 45 x = 450 gallons of 80% must be added to make a 70% solution.

How many gallons of a 80​% antifreeze solution must be mixed with 100 gallons of 25​% antifreeze to get a mixture that is 70​% ​antifreeze? Use the​ six-step method.

How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 70% antifreeze? Use the six-step method.