KennyFulker
22

# How to find the area of a regular hexagon?

foremy hexagon consists of 6 equilateral triangles area of an equilateral triangle: $A=\frac{a^2\sqrt{3}}{4}$ field of a regular hexagon is: $A= \not6^3 * \frac{a^2\sqrt{3}}{\not4^2}=\frac{3a^2\sqrt{3}}{2}$