Socialcar
Project
Sign in
Ask The Question
English
French
Spanish
Portuguese
Polish
Romanian
Mathematics
Toniamcclennan
Feb 4, 2018, 11:09:00 AM
17
If 0° < x° < 90° and sin x = 1/2 , then cos x = ?
+1
(
1
) Answers
Nakonechny603
Feb 4, 2018, 2:53:36 PM
Sinx = opps/hyp = 1/2 2^2 = 1^2 + x^2 x = sqrt(3) = adj Cosx = adj/hyp = sqrt(3)/2
Add answer
Sign in
Sign up
Related Questions
If 0° < x° < 90° and sin x = 1/2 , then cos x = ?
if tan x = 4/5 and 0 < x < π/2, then sin x =
If tan x = 3/4 and 0◦ ≤ x◦ ≤ 90◦, then cos x =? Please explain the work behind the solution
if cos 90=0 , then the sin 0=
solve for all radian solutions and x if 0 sin x +2sin x cos x=0
If 0 is an acute angle and sin 0 = 1/2 then cos 0 =
Solve the equation cos x° = sin 40°, where 0 < x < 90. x = 40 x = 90 x = 50 x = 20
Solve the equation cos x° = sin 40°, where 0 < x < 90.
solve the equation sin (x° - 20°) = cos 42° for x, where 0 < x <90
Tan x = 1/3 and cos x < 0 , find the value of sin x .