(2) Answers
[latex] \frac{\sqrt{3}}{\sqrt{5}-\sqrt{2}}=\\= \frac{\sqrt{3}}{\sqrt{5}-\sqrt{2}}\ \cdot\ \frac{\sqrt{5}+\sqrt2}{\sqrt{5}+\sqrt{2}}=\\=\frac{\sqrt3\cdot(\sqrt5+\sqrt2)}{(\sqrt5-\sqrt2)(\sqrt5+\sqrt2)}=\\=\frac{\sqrt{15}+\sqrt6}{5-2}=\\=\frac{\sqrt{15}+\sqrt6}{3}[/latex]
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