Socialcar-Project.eu Logo Socialcar Project
Sign in
Ask The Question
English French Spanish Portuguese Polish Romanian
Mathematics
MozelleDelmage915
Feb 5, 2018, 1:05:40 AM
11

Please solve 2log5 3x=4

+1
(1) Answers
lyssie11234
Feb 5, 2018, 5:25:24 AM

[latex]2log_53x=4;\\\\D:3x>0\to x>0\to x\in\mathbb{R^+}\\\\\\2log_53x=4\ \ \ /:2\\\\log_53x=2\\\\log_53x=log_55^2\iff3x=25\ \ \ /:3\\\\\underline{\underline{x=\frac{25}{3}\in D}}[/latex]

Add answer
Sign in Sign up
Related Questions
Please solve 2log5 3x=4
Solve for x logx+log(x-4)=2log5
3x+4=52 solve for x please?
Please solve: -6(9x+5)-3x+4=-408+x
Can someone please solve this using elimination? y= 3x - 4 y= -3x + 2
Solve 3x+1=10 please
Please solve this: 5(-3x - 2) - (x-3) = -4(4x+5) + 13
solve showing work 14 = 3x + 4 please help I don't understand this
please help solve (2x+1)(3x+2)=12
Solve the equation -6 + 3x = -9 Please help
Categories
  • Advanced Placement (AP)
  • Arts
  • Biology
  • Business
  • Chemistry
  • Computers and Technology
  • English
  • French
  • Geography
  • German
  • Health
  • History
  • Mathematics
  • Physics
  • SAT
  • Social Studies
  • Spanish
  • World Languages
Languages: English French Spanish Portuguese Polish Romanian
© 2018-2023 Socialcar-Project.eu