PLZ HELP A bag contains 25 pieces of candy and each pieces of candy has a mass of 20 grams. A company produces 200 kilograms of this candy each day. If all of the candy the company produces each day is put into bags, how many bags of candy are produced in one day ? Hint : 1 kilogram = 1,000 grams 2- What is the sum of all values of y that satisfy 6y^2 + 12y - 30 = 0 PLZ show your work !

(1) Answers

number of pieces times weight of each piece=weight of bag 25*20=500grams per 1 bag 200kg=200000g weight of 1 bag times x bags=weight of all 500x=200000 divide both sides by 500 x=400 400 bags per day 2. factor out 6 (6)(y^2+2y-5)=0 reemmber how if we had xy=0, assume x and/or y has to be 0? assume that y^2+2y-5=0 use quadratic formula for ax^2+bx+c=0 x=[latex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/latex] so the sum is [latex] \frac{-b+ \sqrt{b^2-4ac} }{2a} [/latex]+[latex] \frac{-b- \sqrt{b^2-4ac} }{2a} [/latex]=[latex] \frac{-2b}{2a} [/latex]=[latex] \frac{-b}{a} [/latex] easy peasy now 1y^2+2y-5=0 -b/a -2/1 -2 is the sum

Add answer