LizzieChwieroth
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# Simplify: $\frac{72a^{5}b^{3} }{ 84a^{4} b^{2}}$ A) $\frac{2}{9}ab$ B) $\frac{2}{3} a^{2} b$ C) $\frac {2a^{2} }{3b}$ D) $\frac{6}{7} ab$

Divide the whole numbers and subtract the exponents with the like bases. $\sf\dfrac{72}{84}$ Simplify: $\sf\dfrac{6}{7}$ $\sf\dfrac{a^5}{a^4}\rightarrow~a^{5-4}\rightarrow~a^1\rightarrow~a$ $\sf\dfrac{b^3}{b^2}\rightarrow~b^{3-2}\rightarrow~b^1\rightarrow~b$ So we have: $\sf\dfrac{6}{7}ab$
First you find a number you can divide $\frac{72}{84}$ 12 is a common factor for both 72 and 84. 72÷12=6 84÷12= 7 so you answer would be D) $\frac{6}{7}ab$ Hope I helped!