Solve for x&y x+y=34 Log base 2 of x + log base 2 of y =6

x > 0; y > 0; Log base 2 of x + log base 2 of y =6 <=> log base 2 ( xy) = 6 <=> xy = 64; but, x + y = 34 => x = 32 and y = 2 or, x = 2 and y = 34.