Mathematics
BellClermont352
1

Solve the system of equations by substitution. x-8y=36 adn -5x+y=15

+0
(2) Answers
Hannah02

first pick a letter to sibstitute. (I picked x so I'm solving for x) x-8y=36 x-8y+8y=36+8y x=8y+36 Now substitue x with 8y+36 in the equation you did not solve for x. -5x+y=15 -5(8y+36)+y=15 Now solve for y -40y-180+y=15 -39y-180=15 -39y-180+180=15+180 -39y=195 (-39y=195)/-39 y=-5 Now solve for x substituting y with -5 (you may use ether equation) x=8y+36 x=8(-5)+36 x=-40+36 x=-4 Check: x-8y=36 (-4)-8(-5)=36 -4+40=36 36=36 and -5x+y=15 -5(-4)+(-5)=15 20-5=15 15=15

anyacanary

[latex]x-8y=36\\ -5x+y=15\\ \\ x=36+8y\\ -5(36+8y)+y=15\\ -180-40y+y=15\\ -39y=195\ /:(-39)\\ y=-5\\ \\ x=36+8y\\ x=36 +8 \cdot (-5)=36-40=-4\\ \\ y=-5\\ x=-4[/latex]

Add answer