Mathematics
Brendens
11

Suppose an investment of $1,800 doubles in value every 7 years. How much is the investment worth after 42 years?

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(2) Answers
CagedLocksmith

Divide 42 by 7 which equals 6. So 1,800 times 6 = 10,800.

Lesch386

x=2^n(1800) x=2^6(1800) x=$115,200

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