Mathematics
klawren39
12

Suppose an investment of $8,200 doubles in value every 7 years. How much is the investment worth after 28 years

+1
(2) Answers
lilmermaidmia

$32,800 28:7=4 8,200×4=32,800

bonjovifan

Before we start anything, because $8,200 doubles every 7 years, let's do this calculation first:  $8,200 x 2 = $16,400 Next, let's set up the info like so: $16,400 = 7 years        $x     28 years $x = $16,400 x 28 years ÷ 7 years $x = 65,600 Therefore, after 28 years, the investment is worth $65,600. Hope this helps! Message me if you have any questions. :)

Add answer