Set up an equation when n is the number and solve: 10 /= -1/4 The number is less than or equal to -1/4. Hope this helps!

[latex]x-searched\ number\\\\10 \leq 4(2x+3)\\10 \leq 8x+12\ \ \ \ \ \ \ |subtract\ 12\\10-12 \leq 8x\\-2 \leq 8x\ \ \ \ \ \ \ \ \ |:8\\x \geq -\frac{2}{8}\\x \geq -\frac{1}{4}\\\\x\in[\frac{1}{4},+\infty)[/latex]