Mathematics
quinasia
21

The center of a circle is located at (−2, 7) . The radius of the circle is 2. What is the equation of the circle in general form? x2+y2+4x−14y+51=0 x2+y2−4x+14y+51=0 x2+y2+4x−14y+49=0 x2+y2−4x+14y+49=0

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(1) Answers
YolandeSehl667

hello :  an equation is : (x+2)² +(y-7)² = 4 x² +4x+4 +y² -14y +49 = 4  x² +4x+y² -14y +49 = 0 ....( answer : 3)

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