Mathematics
kevv
26

The length of a new rectangular playing field is 4 yards longer than triple the width. if the perimeter of the rectangular playing field is 408 yards, what are it's dimensions?

+2
(1) Answers
Yaree

the length is 4 yards longer than 3width so L = 3W+4 perimeter equal 408 yards perimeter equal 2L +2W = 2(3W+4)+2W  408 = 6W +8 +2W 400=8W W = 50 L = 3*50 +4 = 154 L = 154 W = 50 P = 2L +2W 408 = 2*50 +2*154 408 = 100 +308 408 = 408 hope that this is easy understandably 

Add answer