Mathematics
shan1
16

The perimeter of a basketball court is 268 feet. The area is 4,200 ft^2. Find the dimension of the court.

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(1) Answers
wildweaver3

4200 = lw 268 = 2l+2w L= 4200/w Plug this into perimeter equation and solve for w. Then solve for l by pluging we into the perimeter eqn

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