# Use Newton's method to approximate a root of the equation \cos(x^2 + 3) = x^3 as follows. Let x_1 = 1 be the initial approximation. The second approximation x_2 is?

(1) Answers

x_2 = x_1 - f(x_1) / f ' (x_1) => x_2 = 1 + (cos4 -1 )/ ( 2sin4 + 3) ≈ 1 - 7.64 ≈ - 6.64;

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