What are the coordinates of the focus of the conic section shown below?
y^2-4x+4y-4=0
...?

+1

(1) Answers

Kosterk

the answer is
y^2-4x+4y-4=y^2+4y-4x-4=(y+2)²-4x - 8= 0
it is the same of x + 2 = (1/4 ) (y+2)²
the main formula is x-h= a (y-k)² so h=-2, k= - 2 and a=1/4