Mathematics
Wenwebb1
16

What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)? x2 + y2 − 4x + 2y + 1 = 0 x2 + y2 + 4x − 2y + 1 = 0 x2 + y2 + 4x − 2y + 9 = 0 x2 − y2 + 2x + y + 1 = 0

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(1) Answers
petranajjar

Equation is : ( x + 2 )² + ( y - 1 )² = r² ( - 4 + 2 )² + ( 1 - 1 )² = r² 4 = r², than we will plug in to a formula: ( x + 2 )² + ( y - 1 )² = 4 x² + 4 x + 4 + y² - 2 y +1 = 4 x² + y² + 4 x - 2 y + 1 = 0 Answer: B )

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