What is the total energy of a 175,000kg shuttle orbiting the Earth at 600km above Earth's surface?
(1) Answers
m = 175,000 kg g = 10 m/s^2 h = 600,000 m Ep = mgh Ep = 1050 * 10^9 [J]
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m = 175,000 kg g = 10 m/s^2 h = 600,000 m Ep = mgh Ep = 1050 * 10^9 [J]