Mathematics
OHS
26

When jill started jogging she ran 3/4 mile on the first day 1 1/8 miles on the second day and 1 1/2 miles on the third day if she increased the distance she jogged each day by the same amount how far did she jog on the fifth day ? explain how you found your answer

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Hanington955

1 1/8 - 3/4 =  9/8 - 3/4 = 9/8 - 6/8 = 3/8...so she ran 3/8 miles per day what u have is an arithmetic sequence with a common difference of 3/8. And we are looking for the fifth term... an = a1 + d(n - 1) n = term we want to find = 5 a1 = first term = 3/4 d = common difference = 3/8 now we sub a(5) = 3/4 + 3/8(5 - 1) a(5) = 3/4 + 3/8(4) a(5) = 3/4 + 12/8 a(5) = 6/8 + 12/8 a(5) = 18/8 reduces to 9/4 or 2 1/4 miles <== jogged on 5th day

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