Write an equation in slope intercept form of a line that passes through the point (2,4) and is perpendicular to the graph of x-6y=2
(1) Answers
-6y=2-x y=x/6-1/3 so the slope for this line is 1/6, therefore the slope for line perpendicular to this line is -6 y=mx+b subsitute (2,4)in 4=-6*2+b you get b=16 so the equation is y=-6x+16
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