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natanciubotari
3 feb. 2018, 19:09:00
3
[1/3+1\3:(1-1\3)]:3\2=
+0
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1
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maria1113
4 feb. 2018, 06:01:27
1/3 + 1/3= 2/3 : la 1-1/3 =0 total si apoi iar impartit egal 0
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(3×1/2-1/2)+(1×1/3-1/3)
[1/3+1\3:(1-1\3)]:3\2=
Fie sirurile de cifre a) 1 2 1 2 1 2 1 2... b) 1 2 3 1 2 3 1 2 3 1 2 3... c) 1 2 3 4 1 2 3 4 1...
Calculati: (1 - 1/3 + 1/3^2 - 1/3^3 + ... - 1/3^2011) : (1 - 3^2012)
Efectuati:a) 1^1+2^2+3^3+4^4 b) 4^4-3^3-2^2-1 c) 1^2^3+3^1^2+2^3^1 d) (2+2^2+2^3):(10^1-3)
Ajutati-ma va rog, urgent 1) (1/2 + 2/5) - (1/2 + 1/3) - [(-1/15 + 5/6) - (1/2 + 1/5)]=0 2) 2...
3×1+2×4+1=30 ; 3×1+2×4+1=28 ; 3×1+2×4+1=37 ; 3×1+2×4+1=21
Sa se calculeze suma 1+ 1/3+1/3^2+1/3^3+1/3^4
1. (1+2+3+ .... + 2013) : 2014= 2. (1+2+3+..... + 2014) : 2015= 3. (1+2+3+..... + 14 ) : (1+2...
Calculati (1+2+3+...+14)÷(1+2+3+...6); (1×2×3×...×15)÷(1+2+3+...+15)