rezolvati in multimea numerelor intregi ecuatia x'2-x-6=0

x²-x-6=0 x²-3x+2x-6=0 x(x-3)+2(x-3)=0 (x-3)(x+2)=0 i)x-3=0⇒x₁=3∈Z ii)x+2=0⇒x₂=-2∈ Z S:x∈{-2,3}