Matematică
andreeanedelcu
7

Va rog ajutatima dau coroana! Calculati puterile: 11^{6} : 11^{2} :11 · 11^{3} : 11^{4} = (3^{4} )^{5 } ·5^{4} = 16^{4} ·4^{5} :2^{5} = (5^{3} ) ^{4} · 5^{4} = 27^{5} · 9^{6} : 3^{3} =

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(1) Răspunsuri
laviniaalexia21

1)11^6:11^2=11^4 11^4:11=11^3 11^3×11^3=11^6 11^6:11^4=11^2=121 2) (3^4)^5×5^4= 81^5×5^4= 81^5×625= (81×625)^5 3) 4^5=16^4; 2^5=16^2 16^4×16^4 : 16^2= 16^6 4) (5^3)^4=5^12 5^12×5^4=5^16 5) 9^6=27^5; 3^3=27 37^5×27^5:27=27^9

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